$A$ sample of water under study was found to boil at $102\,^{\circ}C$ at normal temperature and pressure. Is the water pure? Will this water freeze at $0\,^{\circ}C$? Comment.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The boiling point of pure water is $100\,^{\circ}C$ at $1 \text{ atm}$ pressure.
Since the given sample boils at $102\,^{\circ}C$,it indicates the presence of impurities (solutes) in the water.
Therefore,the water is not pure.
Due to the presence of impurities,the freezing point of the water will be depressed,meaning it will freeze at a temperature below $0\,^{\circ}C$.

Explore More

Similar Questions

Which condition out of the following increases the evaporation of water?

What is evaporation?

The gases can be liquefied by

Which is the correct statement?

What is meant by evaporation? How is this process different from boiling?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo