A screen is placed 50,cm from a single slit,w | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The position of the $n^{th}$ minima in a single slit diffraction pattern is given by $y_n = \frac{n \lambda D}{d}$,where $d$ is the slit width,$D$

Vedclass · Accepted Answer

$0.2$

Vedclass · Answer

(B) The position of the $n^{th}$ minima in a single slit diffraction pattern is given by $y_n = \frac{n \lambda D}{d}$,where $d$ is the slit width,$D$ is the distance to the screen,and $\lambda$ is the wavelength.Given: $D = 50\,cm = 0.5\,m$,$\lambda = 6000\,\mathring{A} = 6 	imes 10^{-7}\,m$,and the distance between the first and third minima $\Delta y = 3\,mm = 3 	imes 10^{-3}\,m$.The distance between the $n_1^{th}$ and $n_2^{th}$ minima is $\Delta y = \frac{(n_2 - n_1) \lambda D}{d}$.Substituting $n_2 = 3$ and $n_1 = 1$,we get $\Delta y = \frac{2 \lambda D}{d}$.Rearranging for $d$: $d = \frac{2 \lambda D}{\Delta y}$.$d = \frac{2 	imes (6 	imes 10^{-7}\,m) 	imes (0.5\,m)}{3 	imes 10^{-3}\,m}$.$d = \frac{6 	imes 10^{-7}}{3 	imes 10^{-3}} = 2 	imes 10^{-4}\,m = 0.2\,mm$.

$A$ screen is placed $50\,cm$ from a single slit,which is illuminated with $6000\,\mathring{A}$ light. If the distance between the first and third minima in the diffraction pattern is $3\,mm,$ the width of the slit is ......$mm$.

Similar Questions

Two slits are $1 \,mm$ apart and the screen is located $1 \,m$ away from the slits. $A$ light of wavelength $500 \,nm$ is used. The width of each slit to obtain $10$ maxima of the double slit pattern within the central maximum of the single slit pattern is $\ldots \ldots \ldots \times 10^{-4} \,m$.

The first diffraction minimum due to the single slit diffraction is seen at $\theta = 30^o$ for a light of wavelength $5000 \,\mathring{A}$ falling perpendicularly on the slit. The width of the slit is

$A$ slit of size $0.15 \,cm$ is placed at $2.1 \,m$ from a screen. On illuminating it by a light of wavelength $5 \times 10^{-5} \,cm$,the width of the central maxima will be:

Assertion: The clouds in the sky generally appear to be whitish.
Reason: Diffraction due to clouds is efficient in equal measure at all wavelengths.

$A$ light ray of wavelength $\lambda$ is passing through a pinhole of diameter $D$ and the effect is observed on a screen placed at a distance $L$ from the pinhole. The approximations of geometrical optics are applicable, if

Vedclass Test Series

Exam Paper Generator

Online Exam Module