A shell of mass 0.020 ; kg is fired by a gun | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Mass of the gun,$M = 100 \; kg$.Mass of the shell,$m = 0.020 \; kg$.Muzzle speed of the shell,$v = 80 \; m/s$.Let the recoil speed of the gun be $

Vedclass · Accepted Answer

$0.016$

Vedclass · Answer

(C) Mass of the gun,$M = 100 \; kg$.Mass of the shell,$m = 0.020 \; kg$.Muzzle speed of the shell,$v = 80 \; m/s$.Let the recoil speed of the gun be $V$.Initially,both the gun and the shell are at rest,so the initial momentum of the system is $0$.According to the law of conservation of linear momentum,the final momentum of the system must also be $0$.Final momentum $= mv - MV = 0$.Here,the negative sign indicates that the gun recoils in the direction opposite to the shell.Rearranging the equation: $MV = mv$.$V = \frac{mv}{M} = \frac{0.020 \; kg 	imes 80 \; m/s}{100 \; kg}$.$V = \frac{1.6}{100} \; m/s = 0.016 \; m/s$.

$A$ shell of mass $0.020 \; kg$ is fired by a gun of mass $100 \; kg$. If the muzzle speed of the shell is $80 \; m s^{-1}$,what is the recoil speed in $m/s$ of the gun?

Similar Questions

An artillery piece of mass $M_1$ fires a shell of mass $M_2$ horizontally. Instantaneously after the firing,the ratio of kinetic energy of the artillery and that of the shell is:

$A$ bullet of mass $50 \, g$ is fired from a $5 \, kg$ gun with a velocity of $1 \, km/s$. The speed of recoil of the gun is .......... $m/s$.

The law of conservation of linear momentum is derived by using which of Newton's laws?

$A$ particle of mass $m$ travelling along the $x$-axis with speed $v_0$ shoots out $1/3$ of its mass with a speed $2v_0$ along the $y$-axis. The velocity of the remaining piece is:

$A$ trolley of mass $1000\, kg$ is moving with a velocity of $50\, km/h$. If a mass of $250\, kg$ is added to it,what will be the new velocity in $km/h$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module