A shopkeeper has one spherical laddoo of radi | vedclass

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(C) The volume of a sphere is given by the formula $V = \frac{4}{3} \pi r^3$.Let the radius of the large laddoo be $R = 5 \, cm$ and the radius of the

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$8$

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(C) The volume of a sphere is given by the formula $V = \frac{4}{3} \pi r^3$.Let the radius of the large laddoo be $R = 5 \, cm$ and the radius of the smaller laddoos be $r = 2.5 \, cm$.Since the total amount of material remains the same,the total volume of the smaller laddoos must equal the volume of the large laddoo.Let $n$ be the number of smaller laddoos.$n 	imes (\frac{4}{3} \pi r^3) = \frac{4}{3} \pi R^3$$n = \frac{R^3}{r^3} = (\frac{R}{r})^3$$n = (\frac{5}{2.5})^3 = (2)^3 = 8$.Therefore,$8$ laddoos of radius $2.5 \, cm$ can be made.

$A$ shopkeeper has one spherical laddoo of radius $5 \, cm$. With the same amount of material,how many laddoos of radius $2.5 \, cm$ can be made?

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