Class 10MathematicsPair of Linear Equations in Two VariablesMix Examples - Pair of Linear Equations in Two Variables
Medium$A$ shopkeeper sells $4$ pants and $3$ shirts for Rs. $5000$. The cost of a pair of a pant and a shirt is Rs. $750$. Represent this situation as a pair of linear equations in two variables.
(N/A) Let the cost of one pant be $x$ and the cost of one shirt be $y$.
According to the first condition,the total cost of $4$ pants and $3$ shirts is Rs. $5000$,which can be represented as $4x + 3y = 5000$.
According to the second condition,the cost of one pant and one shirt is Rs. $750$,which can be represented as $x + y = 750$.
Thus,the pair of linear equations is $4x + 3y = 5000$ and $x + y = 750$.
According to the first condition,the total cost of $4$ pants and $3$ shirts is Rs. $5000$,which can be represented as $4x + 3y = 5000$.
According to the second condition,the cost of one pant and one shirt is Rs. $750$,which can be represented as $x + y = 750$.
Thus,the pair of linear equations is $4x + 3y = 5000$ and $x + y = 750$.
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View SolutionWhich of the following groups truly matches the data of Part $I$ with the data of Part $II$?
Part $I$ Part $II$ $1.$ The solution of $2x - y = 4$ and $3x - 2y = 5$ $a.$ $x = 3, y = 2$ $2.$ The solution of $5x - y = 14$ and $4x - 3y = 9$ $b.$ $x = 3, y = 1$ $3.$ The solution of $4x - 3y = 5$ and $3x - y = 5$ $c.$ $x = 2, y = 1$ $4.$ The solution of $3x - 2y = -1$ and $2x - 5y = -8$ $d.$ $x = 1, y = 2$
| Part $I$ | Part $II$ |
| $1.$ The solution of $2x - y = 4$ and $3x - 2y = 5$ | $a.$ $x = 3, y = 2$ |
| $2.$ The solution of $5x - y = 14$ and $4x - 3y = 9$ | $b.$ $x = 3, y = 1$ |
| $3.$ The solution of $4x - 3y = 5$ and $3x - y = 5$ | $c.$ $x = 2, y = 1$ |
| $4.$ The solution of $3x - 2y = -1$ and $2x - 5y = -8$ | $d.$ $x = 1, y = 2$ |
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