A signal of 0.1 , kW is transmitted in a cabl | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The total attenuation in the cable is given by: $	ext{Total Attenuation} = (	ext{Attenuation per km}) 	imes (	ext{Length}) = -5 \, dB/km 	ime

Vedclass · Accepted Answer

$8$

Vedclass · Answer

(D) The total attenuation in the cable is given by: $	ext{Total Attenuation} = (	ext{Attenuation per km}) 	imes (	ext{Length}) = -5 \, dB/km 	imes 20 \, km = -100 \, dB$.The formula for gain in $dB$ is: $	ext{Gain} = 10 \log_{10}(\frac{P_0}{P_i})$.Here,$	ext{Gain} = -100 \, dB$,$P_i = 0.1 \, kW = 100 \, W = 10^2 \, W$.Substituting the values: $-100 = 10 \log_{10}(\frac{P_0}{10^2})$.$-10 = \log_{10}(\frac{P_0}{10^2})$.$10^{-10} = \frac{P_0}{10^2}$.$P_0 = 10^{-10} 	imes 10^2 = 10^{-8} \, W$.Comparing $P_0 = 10^{-8} \, W$ with $10^{-x} \, W$,we get $x = 8$.

$A$ signal of $0.1 \, kW$ is transmitted in a cable. The attenuation of the cable is $-5 \, dB$ per $km$ and the cable length is $20 \, km$. The power received at the receiver is $10^{-x} \, W$. The value of $x$ is ....... .
$[\text{Gain in } dB = 10 \log_{10}(\frac{P_0}{P_i})]$

Similar Questions

For the output of an $AM$ detector circuit to follow the envelope of the carrier wave,which condition must be satisfied? ($T_c$ is the time period of the carrier wave.)

Three signals related to amplitude modulation are shown in the figure. The correct assignment of the signals is

The signal obtained at the output of a microphone is of which type?

$A$ $100\,m$ long antenna is mounted on a $500\,m$ tall building. The complex can become a transmission tower for waves with $\lambda$ (approx) ........ $m$.

In satellite communication,the $6\,\text{GHz}$ frequency is used for........... and the $4\,\text{GHz}$ frequency is used for...........

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$A$ signal of $0.1 \, kW$ is transmitted in a cable. The attenuation of the cable is $-5 \, dB$ per $km$ and the cable length is $20 \, km$. The power received at the receiver is $10^{-x} \, W$. The value of $x$ is ....... .$[\text{Gain in } dB = 10 \log_{10}(\frac{P_0}{P_i})]$