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(D) The mass deposited in a voltameter is given by Faraday's law of electrolysis: $m = Z i t$,where $m$ is the mass,$Z$ is the electrochemical equival

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$16$

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(D) The mass deposited in a voltameter is given by Faraday's law of electrolysis: $m = Z i t$,where $m$ is the mass,$Z$ is the electrochemical equivalent $(E.C.E.)$,$i$ is the current,and $t$ is the time.Given time $t = 0.5 	ext{ hours} = 1800\,s$.For the silver voltameter: $i_1 = \frac{m_1}{Z_1 t} = \frac{2}{1.118 	imes 10^{-3} 	imes 1800} \approx 0.994\,A$.For the copper voltameter: $i_2 = \frac{m_2}{Z_2 t} = \frac{1}{3.294 	imes 10^{-4} 	imes 1800} \approx 1.687\,A$.Since the voltameters are in parallel,the total current $I = i_1 + i_2 = 0.994 + 1.687 = 2.681\,A$.The power supplied by the battery is $P = V 	imes I = 6 	imes 2.681 \approx 16.086\,W$.Thus,the power is approximately $16\,W$.

$A$. Mobility	$P$. $\frac{m}{ne^2 \rho}$
$B$. Electrical conductivity	$Q$. $neAv_{d}$
$C$. Relaxation period	$R$. $\frac{v_{d}}{E}$
$D$. Current	$S$. $\frac{J}{E}$

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