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(A) The effective acceleration due to gravity $g_{eff}$ experienced by the pendulum in a car accelerating with uniform acceleration $a$ is given by $g

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(A) The effective acceleration due to gravity $g_{eff}$ experienced by the pendulum in a car accelerating with uniform acceleration $a$ is given by $g_{eff} = \sqrt{g^2 + a^2}$.The frequency of oscillation $n$ of a simple pendulum is given by $n = \frac{1}{2\pi} \sqrt{\frac{g_{eff}}{l}}$,where $l$ is the length of the pendulum.Substituting $g_{eff}$,we get $n = \frac{1}{2\pi} \sqrt{\frac{\sqrt{g^2 + a^2}}{l}}$.Since $g_{eff} > g$ when the car accelerates,the frequency $n$ increases compared to its value when the car is at rest.

$A$ simple pendulum hangs from the ceiling of a car. If the car accelerates with a uniform acceleration,the frequency of the simple pendulum will

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