(A) In an $RL$ series circuit,the impedance $Z$ is given by $Z = \sqrt{R^2 + X_L^2}$.Here,$X_L = \omega L$ is the inductive reactance.Therefore,$Z = \

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

$\frac{V_0}{\sqrt{R^2 + \omega^2 L^2}}$

(A) In an $RL$ series circuit,the impedance $Z$ is given by $Z = \sqrt{R^2 + X_L^2}$.Here,$X_L = \omega L$ is the inductive reactance.Therefore,$Z = \sqrt{R^2 + (\omega L)^2} = \sqrt{R^2 + \omega^2 L^2}$.The amplitude of the current $I_0$ is given by the ratio of the peak voltage $V_0$ to the impedance $Z$.$I_0 = \frac{V_0}{Z} = \frac{V_0}{\sqrt{R^2 + \omega^2 L^2}}$.

Class 12 Physics Alternating Current RL, RC and LC AC Circuits

Medium

$A$ sinusoidal voltage $V_0 \sin \omega t$ is applied across a series combination of resistance $R$ and inductance $L$. The amplitude of the current in this circuit is

A
$\frac{V_0}{\sqrt{R^2 + \omega^2 L^2}}$
B
$\frac{V_0}{\sqrt{R^2 - \omega^2 L^2}}$
C
$\frac{V_0}{R + \omega L}$
D
$\frac{V_0}{R}$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Physics Questions

Chapter

Alternating Current

Subtopic

RL, RC and LC AC Circuits

An $a.c.$ circuit contains a resistance of $12 \ \Omega$ and an inductor of inductive reactance $5 \ \Omega$. The phase angle between current and potential difference will be

EasyMHT CET 2025

View Solution

An $ac$ voltage is applied to a resistance $R$ and an inductor $L$ in series. If $R$ and the inductive reactance are both equal to $3\,\Omega$,the phase difference between the applied voltage and the current in the circuit is

EasyAIPMT 2011

View Solution

What will be the reading in the voltmeter and ammeter of the circuit shown?

MediumKCET 2021

View Solution

In a $L-R$ circuit of $4 \text{ mH}$ inductance and $3 \text{ } \Omega$ resistance, e.m.f. $E = \cos(1000t) \text{ V}$ is applied. The amplitude of current is (in $\text{ A}$)

DifficultMHT CET 2026

View Solution

$A$ $12\,\Omega$ resistor and a $0.21\,H$ inductor are connected in series to an $ac$ source operating at $20\,V$,$50\,Hz$. The phase angle between the current and the source voltage is.....$^o$

Easy

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

$A$ sinusoidal voltage $V_0 \sin \omega t$ is applied across a series combination of resistance $R$ and inductance $L$. The amplitude of the current in this circuit is

Similar Questions

An $a.c.$ circuit contains a resistance of $12 \ \Omega$ and an inductor of inductive reactance $5 \ \Omega$. The phase angle between current and potential difference will be

An $ac$ voltage is applied to a resistance $R$ and an inductor $L$ in series. If $R$ and the inductive reactance are both equal to $3\,\Omega$,the phase difference between the applied voltage and the current in the circuit is

What will be the reading in the voltmeter and ammeter of the circuit shown?

In a $L-R$ circuit of $4 \text{ mH}$ inductance and $3 \text{ } \Omega$ resistance, e.m.f. $E = \cos(1000t) \text{ V}$ is applied. The amplitude of current is (in $\text{ A}$)

$A$ $12\,\Omega$ resistor and a $0.21\,H$ inductor are connected in series to an $ac$ source operating at $20\,V$,$50\,Hz$. The phase angle between the current and the source voltage is.....$^o$

Vedclass Test Series

Exam Paper Generator

Online Exam Module