A siphon in use is demonstrated in the follow | vedclass

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(C) Both points $P$ and $S$ are located at the free surfaces of the liquid in the two containers.Since both containers are open to the atmosphere,the

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(C) Both points $P$ and $S$ are located at the free surfaces of the liquid in the two containers.Since both containers are open to the atmosphere,the pressure at both points $P$ and $S$ is equal to the atmospheric pressure $(P_{atm})$.Therefore,the pressure difference between point $P$ and point $S$ is given by $\Delta P = P_P - P_S = P_{atm} - P_{atm} = 0$.

$A$ siphon in use is demonstrated in the following figure. The density of the liquid flowing in the siphon is $1.5 \text{ g/cm}^3$. The pressure difference between the points $P$ and $S$ will be

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