A small sphere of mass m is dropped from a gr | vedclass

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(B) During the first $100 \; m$,the sphere starts from rest and its velocity increases continuously until it reaches the terminal velocity $(v_T)$ at

Vedclass · Accepted Answer

Less than the work done by air friction in the second $100 \; m$

Vedclass · Answer

(B) During the first $100 \; m$,the sphere starts from rest and its velocity increases continuously until it reaches the terminal velocity $(v_T)$ at the $100 \; m$ mark.Since the air friction (viscous force) is proportional to the velocity of the sphere,the force is lower at the beginning and increases as the velocity increases.Work done is defined as the integral of force over distance $(W = \int F \cdot dx)$.Since the velocity is lower on average during the first $100 \; m$ compared to the subsequent $100 \; m$ (where the velocity remains constant at $v_T$),the work done against air friction in the first $100 \; m$ is less than the work done in the second $100 \; m$.

$A$ small sphere of mass $m$ is dropped from a great height. After it has fallen $100 \; m$,it has attained its terminal velocity and continues to fall at that speed. The work done by air friction against the sphere during the first $100 \; m$ of fall is

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