A soap bubble assumes a spherical surface. Wh | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For a soap bubble, the excess pressure inside is given by $\Delta P = P_{in} - P_{out} = \frac{4T}{R}$, where $T$ is the surface tension and $R$ i

Vedclass · Accepted Answer

The pressure of air inside the bubble is less than the atmospheric pressure; that is why the atmospheric pressure has compressed it equally from all sides to give it a spherical shape.

Vedclass · Answer

(C) For a soap bubble, the excess pressure inside is given by $\Delta P = P_{in} - P_{out} = \frac{4T}{R}$, where $T$ is the surface tension and $R$ is the radius of the bubble. This implies that $P_{in} = P_{out} + \frac{4T}{R}$. Since $\frac{4T}{R} > 0$, the pressure inside the bubble is always greater than the atmospheric pressure. Therefore, statement $(C)$ is wrong because it incorrectly claims that the internal pressure is less than the atmospheric pressure.

$A$ soap bubble assumes a spherical surface. Which of the following statements is wrong?

Similar Questions

If two identical mercury drops are combined to form a single drop,then its temperature will

Two soap bubbles, $A$ and $B$, have radii in the ratio $3 : 2$. The ratio of the excess pressure inside bubble $A$ to that of bubble $B$ is:

When two soap bubbles of radius $r_1$ and $r_2$ $(r_2 > r_1)$ coalesce,the radius of curvature of the common surface is:

The radii of two soap bubbles are $r_1$ and $r_2$. In isothermal conditions,they meet together in a vacuum. Then the radius of the resultant bubble is given by

Two soap bubbles of radii $R$ and $r$ come in contact. $R$ is more than $r$. The radius of curvature of the common surface is

Vedclass Test Series

Exam Paper Generator

Online Exam Module