(C) The atomic number of $Na$ is $11$,so $Na^{+}$ has $11 - 1 = 10$ electrons.$O^{2-}$ has $8 + 2 = 10$ electrons.$F^{-}$ has $9 + 1 = 10$ electrons.$

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(C) The atomic number of $Na$ is $11$,so $Na^{+}$ has $11 - 1 = 10$ electrons.$O^{2-}$ has $8 + 2 = 10$ electrons.$F^{-}$ has $9 + 1 = 10$ electrons.$Li^{+}$ has $3 - 1 = 2$ electrons.$Al^{3+}$ has $13 - 3 = 10$ electrons.Therefore,$Na^{+}$ has a different number of electrons from $Li^{+}$.