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(A) $1$. $AgNO_3$ is a well-known compound used in photography due to its light sensitivity.$2$. When $AgNO_3$ reacts with a sodium salt $B$ $(NaBr)$,

Vedclass · Accepted Answer

$A = AgNO_3, B = NaBr, C = AgBr$

Vedclass · Answer

(A) $1$. $AgNO_3$ is a well-known compound used in photography due to its light sensitivity.$2$. When $AgNO_3$ reacts with a sodium salt $B$ $(NaBr)$,it forms a pale yellow precipitate $C$ $(AgBr)$.$3$. The reaction is: $AgNO_3(aq) + NaBr(aq) \rightarrow AgBr(s) + NaNO_3(aq)$.$4$. $AgBr$ is a pale yellow precipitate.$5$. Sodium bromide $(NaBr)$ reacts with concentrated $H_2SO_4$ to produce brown vapours of bromine $(Br_2)$: $2NaBr + 3H_2SO_4 \rightarrow 2NaHSO_4 + SO_2 + Br_2 + 2H_2O$ (or simply $2NaBr + H_2SO_4 \rightarrow Na_2SO_4 + 2HBr$; $2HBr + H_2SO_4 \rightarrow Br_2 + SO_2 + 2H_2O$).$6$. Thus,$A = AgNO_3$,$B = NaBr$,and $C = AgBr$.

$A$ solid $A$ which has photographic effect reacts with the solution of a sodium salt $B$ to give a pale yellow precipitate $C$. The sodium salt $B$ on heating with concentrated $H_2SO_4$ gives brown vapours. Identify $A$,$B$,and $C$.

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