A solid compound X on heating gives CO_2 gas | vedclass

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(D) The given compound $X$ is $CaCO_3$. The reactions are as follows:$1. \ CaCO_3 \xrightarrow{\Delta} CaO + CO_2 \uparrow$ ($X$ decomposes to residue

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$CaCO_3$

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(D) The given compound $X$ is $CaCO_3$. The reactions are as follows:$1. \ CaCO_3 \xrightarrow{\Delta} CaO + CO_2 \uparrow$ ($X$ decomposes to residue $CaO$ and $CO_2$)$2. \ CaO + H_2O 	o Ca(OH)_2$ ($Y$ is calcium hydroxide)$3. \ Ca(OH)_2 + 2CO_2 	o Ca(HCO_3)_2$ ($Z$ is a clear solution of calcium bicarbonate)$4. \ Ca(HCO_3)_2 \xrightarrow{\Delta} CaCO_3 \downarrow + CO_2 \uparrow + H_2O$ (Boiling $Z$ reforms $X$)

$A$ solid compound $X$ on heating gives $CO_2$ gas and a residue. The residue mixed with water forms $Y$. On passing an excess of $CO_2$ through $Y$ in water,a clear solution $Z$ is obtained. On boiling $Z$,compound $X$ is reformed. The compound $X$ is

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$Y$ $\xleftarrow{\Delta ,\, 205^\circ C}$ $CaSO_4 \cdot 2H_2O$ $\xrightarrow{\Delta ,\, 120^\circ C}$ $X$. $X$ and $Y$ are respectively

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