(C) For a compound with $NaCl$ structure, the limiting radius ratio is $0.414$.The radius ratio formula is given by $\frac{r^+}{r^-} = 0.414$.Given th

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(C) For a compound with $NaCl$ structure, the limiting radius ratio is $0.414$.The radius ratio formula is given by $\frac{r^+}{r^-} = 0.414$.Given that the radius of the cation $r^+ = 100 \ pm$, we substitute this into the equation:$\frac{100}{r^-} = 0.414$$r^- = \frac{100}{0.414} \approx 241.54 \ pm$.Rounding to the nearest option, the radius of the anion is $241.5 \ pm$.

Class 12 Chemistry Solid State Crystallography and Lattice

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$A$ solid compound $XY$ has $NaCl$ structure. If the radius of the cation is $100 \ pm,$ the radius of the anion $(Y^-)$ will be .............. $pm$.

AIPMT 2011 All AIPMT

A
$275.1$
B
$322.5$
C
$241.5$
D
$165.7$

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$A$ solid compound $XY$ has $NaCl$ structure. If the radius of the cation is $100 \ pm,$ the radius of the anion $(Y^-)$ will be .............. $pm$.

Similar Questions

For an orthorhombic crystal system,the axial lengths are $a \neq b \neq c$. What are the axial angles?

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How many lattice points are there in one unit cell of each of the following lattices?
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