A solid cylinder of length L and radius r is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Since both objects have the same volume,we have $a^3 = \pi r^2 L$  --- $(1)$.The amount of radiation emitted $Q$ is proportional to the surface ar

Vedclass · Accepted Answer

$\frac{a}{3r}$

Vedclass · Answer

(A) Since both objects have the same volume,we have $a^3 = \pi r^2 L$  --- $(1)$.The amount of radiation emitted $Q$ is proportional to the surface area $A$ of the object,given that the temperature and material are the same for both $(Q = \sigma A e T^4 t)$.For the cylinder,the curved surface area is $A_{	ext{cyl}} = 2\pi r L$ (neglecting flat ends).For the cube,the total surface area is $A_{	ext{cube}} = 6a^2$.The ratio of radiation is $\frac{R_{	ext{cyl}}}{R_{	ext{cube}}} = \frac{2\pi r L}{6a^2}$.From equation $(1)$,we know $\pi r^2 L = a^3$,so $L = \frac{a^3}{\pi r^2}$.Substituting $L$ into the ratio: $\frac{R_{	ext{cyl}}}{R_{	ext{cube}}} = \frac{2\pi r (a^3 / \pi r^2)}{6a^2} = \frac{2a^3 / r}{6a^2} = \frac{2a}{6r} = \frac{a}{3r}$.

Similar Questions

What is the speed of heat radiation equal to?

If a vessel with black spots is heated to a very high temperature and then taken into a dark room,then:

When we enter an air-conditioned room,we feel cold. This can be explained by:

Why are the bottom layers of cooking vessels kept black in color?

$A$ sphere,a cube,and a thin circular plate,all made of the same material and having the same mass,are heated to the same temperature of $200^{\circ} C$. When these are left in a room,which one reaches room temperature the fastest?

Vedclass Test Series

Exam Paper Generator

Online Exam Module