A solution contains 25% {H_2}O,25% {C_2}{H_5} | vedclass

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(C) Let the total mass of the solution be $100 \ g$. Mass of ${H_2}O = 25 \ g$,Mass of ${C_2}{H_5}OH = 25 \ g$,and Mass of ${CH_3}COOH = 50 \ g$. Mole

Vedclass · Accepted Answer

$0.502$

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(C) Let the total mass of the solution be $100 \ g$. Mass of ${H_2}O = 25 \ g$,Mass of ${C_2}{H_5}OH = 25 \ g$,and Mass of ${CH_3}COOH = 50 \ g$. Moles of ${H_2}O = \frac{25 \ g}{18 \ g/mol} = 1.389 \ mol$. Moles of ${C_2}{H_5}OH = \frac{25 \ g}{46 \ g/mol} = 0.543 \ mol$. Moles of ${CH_3}COOH = \frac{50 \ g}{60 \ g/mol} = 0.833 \ mol$. Total moles $= 1.389 + 0.543 + 0.833 = 2.765 \ mol$. Mole fraction of ${H_2}O = \frac{	ext{moles of } {H_2}O}{	ext{total moles}} = \frac{1.389}{2.765} \approx 0.502$.

$A$ solution contains $25\%$ ${H_2}O$,$25\%$ ${C_2}{H_5}OH$ and $50\%$ ${CH_3}COOH$ by mass. The mole fraction of ${H_2}O$ would be

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