A solution contains 50 , g of sugar in 350 , | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The concentration of a solution is calculated using the formula:$	ext{Concentration} = \frac{	ext{Mass of solute}}{	ext{Mass of solution}} 	im

Vedclass · Accepted Answer

$12.5$

Vedclass · Answer

(A) The concentration of a solution is calculated using the formula:$	ext{Concentration} = \frac{	ext{Mass of solute}}{	ext{Mass of solution}} 	imes 100$Here,the mass of the solute (sugar) = $50 \, g$.The mass of the solvent (water) = $350 \, g$.The total mass of the solution = $	ext{Mass of solute} + 	ext{Mass of solvent} = 50 \, g + 350 \, g = 400 \, g$.Now,substituting the values into the formula:$	ext{Concentration} = \frac{50}{400} 	imes 100 = \frac{1}{8} 	imes 100 = 12.5 \%$.Thus,the concentration of the solution is $12.5 \%$.

$A$ solution contains $50 \, g$ of sugar in $350 \, g$ of water. Calculate the concentration of the solution in terms of mass by mass percentage of the solution. (in $\%$)

Similar Questions

Answer the following:
$(a)$ Under which category of mixtures will you classify alloys and why?
$(b)$ $A$ solution is always a liquid. Comment.
$(c)$ Can a solution be heterogeneous?

An element is sonorous and highly ductile. Under which category would you classify this element? What other characteristics do you expect the element to possess?

$(a)$ What is the effect of temperature on the solubility of a solid in a liquid?
$(b)$ Why is it possible to distinguish the particles of solute from those of solvent in a suspension?

What is chromatography? Mention its applications.

What happens when a saturated solution is heated?

Vedclass Test Series

Exam Paper Generator

Online Exam Module