A solution of Ph_3CCO_2H in concentrated H_2S | vedclass

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Question

(C) When $Ph_3CCO_2H$ is dissolved in concentrated $H_2SO_4$,it undergoes protonation followed by the loss of $CO$ to form a stable triphenylmethyl ca

Vedclass · Accepted Answer

$Ph_3COCH_3$

Vedclass · Answer

(C) When $Ph_3CCO_2H$ is dissolved in concentrated $H_2SO_4$,it undergoes protonation followed by the loss of $CO$ to form a stable triphenylmethyl carbocation $(Ph_3C^+)$.When this solution is poured into methanol $(CH_3OH)$,the methanol acts as a nucleophile and attacks the $Ph_3C^+$ carbocation.This results in the formation of methyl triphenylmethyl ether,which is $Ph_3COCH_3$ (also written as $Ph_3C-O-CH_3$).Therefore,the product $(X)$ is $Ph_3COCH_3$.

$A$ solution of $Ph_3CCO_2H$ in concentrated $H_2SO_4$ gives $(X)$ when poured into methanol. $X$ is

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