$A$ solution of $FeCl_3$ when treated with $K_4[Fe(CN)_6]$ gives a Prussian blue precipitate due to the formation of:

  • A
    $K[Fe_2(CN)_6]$
  • B
    $Fe[Fe(CN)_6]$
  • C
    $Fe_3[Fe(CN)_6]_2$
  • D
    $Fe_4[Fe(CN)_6]_3$

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