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(B) The Doppler shift in wavelength $\Delta \lambda$ is given by the formula: $\Delta \lambda = \lambda \frac{v}{c}$.Given:$\lambda = 5700 \ \mathring

Vedclass · Accepted Answer

$1.90$

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(B) The Doppler shift in wavelength $\Delta \lambda$ is given by the formula: $\Delta \lambda = \lambda \frac{v}{c}$.Given:$\lambda = 5700 \ \mathring{A} = 5700 	imes 10^{-10} \ m$$v = 100 \ km/s = 100 	imes 10^3 \ m/s = 10^5 \ m/s$$c = 3 	imes 10^8 \ m/s$Substituting the values:$\Delta \lambda = 5700 	imes \frac{10^5}{3 	imes 10^8} \ \mathring{A}$$\Delta \lambda = \frac{5700}{3} 	imes 10^{-3} \ \mathring{A}$$\Delta \lambda = 1900 	imes 10^{-3} \ \mathring{A} = 1.90 \ \mathring{A}$.

$A$ star is moving away from the Earth with a velocity of $100 \ km/s$. If the velocity of light is $3 \times 10^8 \ m/s$,then the shift of its spectral line of wavelength $5700 \ \mathring{A}$ due to the Doppler effect will be ..... $\mathring{A}$.

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