A steady flow of water passes along a horizon | vedclass

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(D) According to the equation of continuity,$A_X v_X = A_Y v_Y$. Since the area of cross-section at $X$ is greater than at $Y$ $(A_X > A_Y)$,the veloc

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the manometer at $P$ shows greater pressure than at $Q$

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(D) According to the equation of continuity,$A_X v_X = A_Y v_Y$. Since the area of cross-section at $X$ is greater than at $Y$ $(A_X > A_Y)$,the velocity of water at $X$ must be less than at $Y$ $(v_X According to Bernoulli's theorem for a horizontal tube,$P_X + \frac{1}{2} \rho v_X^2 = P_Y + \frac{1}{2} \rho v_Y^2$. Since $v_Y > v_X$,the kinetic energy per unit volume at $Y$ is greater than at $X$. To maintain the constant sum,the pressure at $X$ must be greater than the pressure at $Y$ $(P_X > P_Y)$.Therefore,the manometer at $P$ (measuring pressure at $X$) will show a higher pressure than the manometer at $Q$ (measuring pressure at $Y$).

$A$ steady flow of water passes along a horizontal tube from a wide section $X$ to the narrower section $Y$,see figure. Manometers are placed at $P$ and $Q$ at the sections. Which of the statements $A, B, C, D$ is most correct?

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