A stretched wire of length 110 cm is divided | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For a stretched wire,the frequency $n$ is inversely proportional to the length $l$ (i.e.,$n \propto 1/l$),assuming tension and mass per unit lengt

Vedclass · Accepted Answer

$60 \ cm, 30 \ cm, 20 \ cm$

Vedclass · Answer

(B) For a stretched wire,the frequency $n$ is inversely proportional to the length $l$ (i.e.,$n \propto 1/l$),assuming tension and mass per unit length remain constant.Therefore,$n_1 l_1 = n_2 l_2 = n_3 l_3 = k$.Given the ratio of frequencies $n_1 : n_2 : n_3 = 1 : 2 : 3$,we have:$l_1 : l_2 : l_3 = 1/1 : 1/2 : 1/3 = 6 : 3 : 2$.Let the lengths be $6x, 3x, 2x$.The total length is $6x + 3x + 2x = 110 \ cm$.$11x = 110 \ cm \Rightarrow x = 10 \ cm$.Thus,the lengths are $l_1 = 6(10) = 60 \ cm$,$l_2 = 3(10) = 30 \ cm$,and $l_3 = 2(10) = 20 \ cm$.

$A$ stretched wire of length $110 \ cm$ is divided into three segments whose frequencies are in the ratio $1 : 2 : 3$. Their lengths must be

Similar Questions

If the lines $4x + 3y - 1 = 0$,$x - y + 5 = 0$,and $kx + 5y - 3 = 0$ are concurrent,then $k$ is equal to:

$A$ small metal ball is suspended in a uniform electric field with the help of an insulated thread. If a high-energy $X$-ray beam falls on the ball,then the ball

Compound $A$ $(C_3H_6O)$ undergoes the following reactions to form $B$ and $C$. Identify $A$,$B$,and $C$.

Two conducting circular loops of radii $R_1$ and $R_2$ are placed in the same plane with their centres coinciding. If $R_1 >> R_2$,the mutual inductance $M$ between them will be directly proportional to

Which of the following is a redox reaction?

Vedclass Test Series

Exam Paper Generator

Online Exam Module