(C) The Arrhenius equation is given by $k = A \times e^{-\frac{E_a}{RT}}$.Taking the natural logarithm on both sides,we get $\ln k = \ln A - \frac{E_a

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(C) The Arrhenius equation is given by $k = A \times e^{-\frac{E_a}{RT}}$.Taking the natural logarithm on both sides,we get $\ln k = \ln A - \frac{E_a}{R} \times (\frac{1}{T})$.This equation is in the form of a straight line $y = mx + c$,where $y = \ln k$,$x = \frac{1}{T}$,$m = -\frac{E_a}{R}$ (slope),and $c = \ln A$ (intercept).Therefore,a plot of $\ln k$ versus $\frac{1}{T}$ yields a straight line.

Class 12 Chemistry Chemical Kinetics Collision theory, Energy of activation and Arrhenius equation

Medium

$A$ student determined the value of the rate constant,$k$,for a chemical reaction at several different temperatures. Which of the following graphs of the student's data would give a straight line?

A
$k$ vs $T$
B
$k$ vs $(\frac{1}{T})$
C
$\ln k$ vs $(\frac{1}{T})$
D
$\ln k$ vs $E_a$

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Class 12 Questions

Class 12

Chemistry Questions

Chapter

Chemical Kinetics

Subtopic

Collision theory, Energy of activation and Arrhenius equation

Explain the rate of reaction with energy of activation and temperature with the help of the Arrhenius equation and state its importance.

Difficult

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Half life of a first order reaction is $900 \ \text{min}$ at $400 \ K$. Find its half life at $300 \ K$. Given: $\frac{E_a}{2.303 \ R} = 1.3056 \times 10^3 \ K$. (in $\text{min}$)

MediumMHT CET 2025

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For an endothermic reaction,the energy of activation is $E_a$ and the enthalpy of reaction is $\Delta H$ (both in $kJ/mol$). The minimum value of $E_a$ will be:

MediumAIPMT 2010

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Activation energy for the acid catalysed hydration of sucrose is $6.22 \ kJ \ mol^{-1}$,while the activation energy is only $2.15 \ kJ \ mol^{-1}$ when hydrolysis is catalysed by the enzyme sucrase. Explain.

Medium

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If $E_f$ and $E_r$ are the activation energies of forward and reverse reactions and the reaction is known to be exothermic,then

Easy

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$A$ student determined the value of the rate constant,$k$,for a chemical reaction at several different temperatures. Which of the following graphs of the student's data would give a straight line?

Similar Questions

Explain the rate of reaction with energy of activation and temperature with the help of the Arrhenius equation and state its importance.

Half life of a first order reaction is $900 \ \text{min}$ at $400 \ K$. Find its half life at $300 \ K$. Given: $\frac{E_a}{2.303 \ R} = 1.3056 \times 10^3 \ K$. (in $\text{min}$)

For an endothermic reaction,the energy of activation is $E_a$ and the enthalpy of reaction is $\Delta H$ (both in $kJ/mol$). The minimum value of $E_a$ will be:

Activation energy for the acid catalysed hydration of sucrose is $6.22 \ kJ \ mol^{-1}$,while the activation energy is only $2.15 \ kJ \ mol^{-1}$ when hydrolysis is catalysed by the enzyme sucrase. Explain.

If $E_f$ and $E_r$ are the activation energies of forward and reverse reactions and the reaction is known to be exothermic,then

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