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(B) The fundamental frequency $f_0$ of a closed organ pipe of length $l$ is given by $f_0 = \frac{v}{4l}$,where $v$ is the speed of sound in air.As wa

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first increases and then becomes constant

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(B) The fundamental frequency $f_0$ of a closed organ pipe of length $l$ is given by $f_0 = \frac{v}{4l}$,where $v$ is the speed of sound in air.As water is poured into the pipe,the length of the air column $l$ decreases.Since $f_0 \propto \frac{1}{l}$,as $l$ decreases,the fundamental frequency $f_0$ increases.Eventually,the water level reaches a point where the rate of water inflow equals the rate of water outflow through the hole at the bottom.At this point,the water level becomes constant,and consequently,the length of the air column $l$ becomes constant.Therefore,the fundamental frequency $f_0$ first increases and then becomes constant.

$A$ sufficiently long closed organ pipe has a small hole at its bottom. Initially,the pipe is empty. Water is poured into the pipe at a constant rate. The fundamental frequency of the air column in the pipe

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