A sum of Rs. 340.68 is distributed among L,M, | vedclass

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(A) Let the amount received by $N$ be $x$.Given that $L$ gets $Rs. 5.72$ more than $N$,so $L = x + 5.72$.Given that $M$ gets $Rs. 2.24$ more than $L$,

Vedclass · Accepted Answer

$109$

Vedclass · Answer

(A) Let the amount received by $N$ be $x$.Given that $L$ gets $Rs. 5.72$ more than $N$,so $L = x + 5.72$.Given that $M$ gets $Rs. 2.24$ more than $L$,so $M = (x + 5.72) + 2.24 = x + 7.96$.The total sum is $Rs. 340.68$,so $L + M + N = 340.68$.Substituting the expressions in terms of $x$: $(x + 5.72) + (x + 7.96) + x = 340.68$.$3x + 13.68 = 340.68$.$3x = 340.68 - 13.68 = 327$.$x = 327 / 3 = 109$.Therefore,$N$ gets $Rs. 109$.

$A$ sum of $Rs. 340.68$ is distributed among $L$,$M$,and $N$ such that $L$ gets $Rs. 5.72$ more than $N$ and $M$ gets $Rs. 2.24$ more than $L$. Find the amount $N$ gets (in $Rs.$).

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