A swimmer covers a distance of 28, km against | vedclass

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(B) Let the speed of the swimmer in still water be $u\, km/h$ and the speed of the current be $v\, km/h$.Speed of the swimmer upstream (against the cu

Vedclass · Accepted Answer

$1.5$

Vedclass · Answer

(B) Let the speed of the swimmer in still water be $u\, km/h$ and the speed of the current be $v\, km/h$.Speed of the swimmer upstream (against the current) $= u - v = \frac{28}{4} = 7\, km/h$.Speed of the swimmer downstream (in the direction of the current) $= u + v = \frac{40}{4} = 10\, km/h$.To find the speed of the current $(v)$,we subtract the upstream speed from the downstream speed and divide by $2$:$v = \frac{(u + v) - (u - v)}{2} = \frac{10 - 7}{2} = \frac{3}{2} = 1.5\, km/h$.Thus,the speed of the current is $1.5\, km/h$.

$A$ swimmer covers a distance of $28\, km$ against the current and $40\, km$ in the direction of the current. If in each case he takes $4\, hours$,then the speed of the current is..........$km/h$.

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