$A$ taut string fixed at both ends vibrates in its $n^{th}$ overtone. The distance between adjacent Node and Antinode is found to be $d$. If the length of the string is $L$,then:

  • A
    $L = 2d (n + 1)$
  • B
    $L = d (n + 1)$
  • C
    $L = 2dn$
  • D
    $L = 2d (n - 1)$

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