A team of 8 persons participates in a shootin | vedclass

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(B) Let the actual total score of the team be $x$.When the best marksman scores $92$ instead of $85$, the total score increases by $(92 - 85) = 7$.The

Vedclass · Accepted Answer

$665$

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(B) Let the actual total score of the team be $x$.When the best marksman scores $92$ instead of $85$, the total score increases by $(92 - 85) = 7$.The new total score becomes $(x + 7)$.The new average is given as $84$ for $8$ persons.Using the formula: $	ext{Average} = \frac{	ext{Total Sum}}{	ext{Number of persons}}$$84 = \frac{x + 7}{8}$$x + 7 = 84 	imes 8$$x + 7 = 672$$x = 672 - 7$$x = 665$Therefore, the total points the team actually scored is $665$.

$A$ team of $8$ persons participates in a shooting competition. If the best marksman had scored $92$ points instead of $85$ points, the average score for the team would have been $84$. What was the total number of points the team actually scored?

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