$A$ telegraph line of length $100 \, km$ has a capacity of $0.01 \, \mu F/km$ and it carries an alternating current at $0.5 \, kHz$. If minimum impedance is required, then the value of the inductance that needs to be introduced in series is . . . . . . $mH$. (Take $\pi = \sqrt{10}$)

  • A
    $99$
  • B
    $101$
  • C
    $105$
  • D
    $100$

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In a series $LCR$ circuit,the capacitance is changed from $C$ to $4C$. To keep the resonance frequency unchanged,the new inductance should be:

$A$ series $LCR$ circuit is connected to a $45 \sin (\omega t) \text{ V}$ source. The resonant angular frequency of the circuit is $10^5 \text{ rad s}^{-1}$ and current amplitude at resonance is $I_0$. When the angular frequency of the source is $\omega = 8 \times 10^4 \text{ rad s}^{-1}$, the current amplitude in the circuit is $0.05 I_0$. If $L = 50 \text{ mH}$, match each entry in List-$I$ with an appropriate value from List-$II$ and choose the correct option.
List-$I$List-$II$
$(P)$ $I_0$ in $\text{mA}$$(1)$ $44.4$
$(Q)$ The quality factor of the circuit$(2)$ $18$
$(R)$ The bandwidth of the circuit in $\text{rad s}^{-1}$$(3)$ $400$
$(S)$ The peak power dissipated at resonance in $\text{Watt}$$(4)$ $2250$
$(5)$ $500$

In the given $LCR$ circuit,the voltage across the terminals of the resistance and the current in the circuit will be:

$A$ series $LCR$ circuit with $L=0.12\, H$,$C=480\, nF$,$R=23\, \Omega$ is connected to a $230\, V$ variable frequency supply.
$(a)$ What is the source frequency for which current amplitude is maximum? Obtain this maximum value.
$(b)$ What is the source frequency for which average power absorbed by the circuit is maximum? Obtain the value of this maximum power.
$(c)$ For which frequencies of the source is the power transferred to the circuit half the power at resonant frequency? What is the current amplitude at these frequencies?
$(d)$ What is the $Q$-factor of the given circuit?

In an $LCR$ series circuit,if the frequency is increased,the impedance of the circuit

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