A telescope of diameter 2 m uses light of wa | vedclass

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Question

(C) The minimum angular separation (limit of resolution) $\Delta 	heta$ for a telescope is given by the formula: $\Delta 	heta = \frac{1.22 \lambda}

Vedclass · Accepted Answer

$0.31 	imes 10^{-6} \ rad$

Vedclass · Answer

(C) The minimum angular separation (limit of resolution) $\Delta 	heta$ for a telescope is given by the formula: $\Delta 	heta = \frac{1.22 \lambda}{d}$.Here,the wavelength $\lambda = 5000 \ \mathring{A} = 5000 	imes 10^{-10} \ m = 5 	imes 10^{-7} \ m$.The diameter of the telescope aperture $d = 2 \ m$.Substituting these values into the formula:$\Delta 	heta = \frac{1.22 	imes 5 	imes 10^{-7}}{2} \ rad$.$\Delta 	heta = 0.61 	imes 5 	imes 10^{-7} \ rad = 3.05 	imes 10^{-7} \ rad$.Rounding to the nearest provided option,we get $\Delta 	heta \approx 0.31 	imes 10^{-6} \ rad$.

$A$ telescope of diameter $2 \ m$ uses light of wavelength $5000 \ \mathring{A}$ for viewing stars. The minimum angular separation between two stars whose image is just resolved by this telescope is

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