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(D) The speed of the thief's jeep is $v_t = 9 \, m/s$.The speed of the policeman's motorcycle is $v_p = 10 \, m/s$.The relative velocity of the police

Vedclass · Accepted Answer

$100$

Vedclass · Answer

(D) The speed of the thief's jeep is $v_t = 9 \, m/s$.The speed of the policeman's motorcycle is $v_p = 10 \, m/s$.The relative velocity of the policeman with respect to the thief is $v_{rel} = v_p - v_t = 10 \, m/s - 9 \, m/s = 1 \, m/s$.The initial separation between the policeman and the thief is $d = 100 \, m$.The time taken to catch the thief is given by $t = \frac{d}{v_{rel}}$.Substituting the values,$t = \frac{100 \, m}{1 \, m/s} = 100 \, s$.

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