A thief is stopped by a policeman from a dist | vedclass

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Question

(D) Initial distance between the policeman and the thief $= 150\, m$.Relative speed of the policeman with respect to the thief $= 9\, km/h - 7\, km/h

Vedclass · Accepted Answer

$525$

Vedclass · Answer

(D) Initial distance between the policeman and the thief $= 150\, m$.Relative speed of the policeman with respect to the thief $= 9\, km/h - 7\, km/h = 2\, km/h$.Converting relative speed to $m/s$: $2 	imes \frac{5}{18} = \frac{5}{9}\, m/s$.Time taken by the policeman to overtake the thief $= \frac{	ext{Distance}}{	ext{Relative Speed}} = \frac{150}{5/9} = 150 	imes \frac{9}{5} = 270\, s$.Speed of the thief in $m/s = 7 	imes \frac{5}{18} = \frac{35}{18}\, m/s$.Distance covered by the thief in $270\, s = 	ext{Speed} 	imes 	ext{Time} = \frac{35}{18} 	imes 270 = 35 	imes 15 = 525\, m$.

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