$A$ transistor has a current amplification factor of $60$. In a $CE$ amplifier, input resistance is $1 \, k\Omega$ and output voltage is $0.01 \, V$. The transconductance is (in $SI$ units)

In the following common emitter configuration, an $NPN$ transistor with current gain $\beta = 100$ is used. The output voltage of the amplifier will be

In the common-base configuration,a transistor has a current amplification factor of $0.95$. If the transistor is used in a common-emitter configuration and the base current changes by $2 \mu A$,then the change in the collector current is: (in $\mu A$)

The input characteristics of a transistor in $CE$ mode is the graph obtained by plotting

An oscillator is nothing but an amplifier with

The voltage gain of a transistor in common emitter configuration is $160$. The resistances in base and collector sides of the circuit are $1 \text{ k}\Omega$ and $4 \text{ k}\Omega$ respectively. If the change in base current is $100 \mu A$, then the change in output current is: