A transistor is connected in common emitter ( | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The current gain $\beta$ in common emitter configuration is related to $\alpha$ by the formula $\beta = \frac{\alpha}{1 - \alpha}$.Substituting $\

Vedclass · Accepted Answer

$26$

Vedclass · Answer

(C) The current gain $\beta$ in common emitter configuration is related to $\alpha$ by the formula $\beta = \frac{\alpha}{1 - \alpha}$.Substituting $\alpha = 0.96$,we get $\beta = \frac{0.96}{1 - 0.96} = \frac{0.96}{0.04} = 24$.The collector current $I_{C}$ is determined by the voltage drop across the collector resistor $R_C = 800 \ \Omega$:$I_{C} = \frac{V_{drop}}{R_C} = \frac{0.5 \ V}{800 \ \Omega} = 0.000625 \ A = 0.625 	imes 10^{-3} \ A$.The base current $I_{B}$ is given by $I_{B} = \frac{I_{C}}{\beta}$.Substituting the values,$I_{B} = \frac{0.625 	imes 10^{-3} \ A}{24} \approx 0.02604 	imes 10^{-3} \ A = 26.04 	imes 10^{-6} \ A$.Thus,the base current is approximately $26 \ \mu A$.

$A$ transistor is connected in common emitter $(CE)$ configuration. The collector supply is $8 \ V$ and the voltage drop across a resistor of $800 \ \Omega$ in the collector circuit is $0.5 \ V$. If the current gain factor $\alpha$ is $0.96$,find the base current in $\mu A$.

Similar Questions

If $ad-bc \neq 0$,then the area (in sq. units) of the parallelogram formed by the lines $ax+by+2=0$,$ax+by+5=0$,$cx+dy+3=0$ and $cx+dy+7=0$ is

Give signs used for floral formula.

Which of the following is the chemical formula of dolomite?

The conditions under which transpiration would be most rapid are:

The solution set of $(5 + 4\cos \theta )(2\cos \theta + 1) = 0$ in the interval $[0, 2\pi ]$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module