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(D) The current gain $\beta$ in a common emitter $(CE)$ configuration is defined as the ratio of the change in collector current $(\Delta I_C)$ to the

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$75$

Vedclass · Answer

(D) The current gain $\beta$ in a common emitter $(CE)$ configuration is defined as the ratio of the change in collector current $(\Delta I_C)$ to the change in base current $(\Delta I_B)$.Given:Change in base current,$\Delta I_B = 200 \ \mu A - 100 \ \mu A = 100 \ \mu A = 100 	imes 10^{-6} \ A$.Change in collector current,$\Delta I_C = 16.5 \ mA - 9 \ mA = 7.5 \ mA = 7.5 	imes 10^{-3} \ A$.Using the formula:$\beta = \frac{\Delta I_C}{\Delta I_B}$Substituting the values:$\beta = \frac{7.5 	imes 10^{-3} \ A}{100 	imes 10^{-6} \ A}$$\beta = \frac{7.5 	imes 10^{-3}}{10^{-4}}$$\beta = 7.5 	imes 10^{1} = 75$.Therefore,the value of current gain $\beta$ is $75$.

$A$ transistor is operated in $CE$ configuration at $V_{CC} = 2 \ V$ such that a change in base current from $100 \ \mu A$ to $200 \ \mu A$ produces a change in the collector current from $9 \ mA$ to $16.5 \ mA$. The value of current gain,$\beta$ is .........

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