A transistor is used in an amplifier circuit | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given: Change in base current $\Delta i_{B} = 100 \,\mu A = 100 	imes 10^{-6} \,A = 0.1 \,mA$.Change in collector current $\Delta i_{C} = 10 \,mA

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(A) Given: Change in base current $\Delta i_{B} = 100 \,\mu A = 100 	imes 10^{-6} \,A = 0.1 \,mA$.Change in collector current $\Delta i_{C} = 10 \,mA$.Load resistance $R_{L} = 2 \,k \Omega = 2000 \,\Omega$.Input resistance $R_{in} = 1 \,k \Omega = 1000 \,\Omega$.First, calculate the current gain $\beta$:$\beta = \frac{\Delta i_{C}}{\Delta i_{B}} = \frac{10 \,mA}{0.1 \,mA} = 100$.Power gain $A_{P}$ is given by the formula:$A_{P} = \beta^{2} 	imes \frac{R_{L}}{R_{in}}$.Substituting the values:$A_{P} = (100)^{2} 	imes \frac{2000 \,\Omega}{1000 \,\Omega} = 10000 	imes 2 = 20000$.$A_{P} = 2 	imes 10^{4}$.Comparing this with $x 	imes 10^{4}$, we get $x = 2$.

Similar Questions

In the transistor circuit shown,the base current is $35 \mu A$. The value of the resistor $R_b$ is......$ k \Omega$.

$A$ common emitter amplifier circuit,built using an $npn$ transistor,is shown in the figure. Its $dc$ current gain is $250$,$R_C = 1\,k\Omega$ and $V_{CC} = 10\,V$. What is the minimum base current for $V_{CE}$ to reach saturation? (in $\mu A$)

In a $CE$ circuit,the collector of a transistor is kept at a constant voltage $V_C = 1.5 \ V$. When the base current changes from $100 \ \mu A$ to $150 \ \mu A$,the collector current changes from $5 \ mA$ to $10 \ mA$. The current gain $\beta$ for this transistor is:

In a $CE$-transistor feedback oscillator circuit,the phase difference between input and output signal is

Vedclass Test Series

Exam Paper Generator

Online Exam Module