A transmitting antenna has a height of 320, m | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The maximum distance $d$ for line-of-sight communication is given by the formula: $d = \sqrt{2Rh_T} + \sqrt{2Rh_R}$.Here,$R$ is the radius of the

Vedclass · Accepted Answer

$224$

Vedclass · Answer

(A) The maximum distance $d$ for line-of-sight communication is given by the formula: $d = \sqrt{2Rh_T} + \sqrt{2Rh_R}$.Here,$R$ is the radius of the Earth $\approx 6400\, km = 6.4 	imes 10^6\, m$.$h_T = 320\, m$ and $h_R = 2000\, m$.Substituting the values:$d = \sqrt{2 	imes 6.4 	imes 10^6 	imes 320} + \sqrt{2 	imes 6.4 	imes 10^6 	imes 2000}$$d = \sqrt{4096 	imes 10^6} + \sqrt{25600 	imes 10^6}$$d = 64000 + 160000 = 224000\, m$.Converting to kilometers: $d = 224\, km$.

$A$ transmitting antenna has a height of $320\, m$ and that of the receiving antenna is $2000\, m$. The maximum distance between them for satisfactory communication in line-of-sight mode is $d$. The value of $d$ is $\ldots \ldots \, km$.

Similar Questions

Broadcasting antennas are generally

The radio horizon of the transmission of an antenna placed on the $20^{\text{th}}$ floor in a shopping mall,where the height of each floor is $2 \,m$,is (Radius of Earth is $6.4 \times 10^6 \,m$): (in $\,km$)

Sky wave propagation is not possible for frequencies

In amplitude modulation,if a message signal of $5 \ kHz$ is modulated by a carrier wave of frequency $900 \ kHz$,then the frequencies of the side bands are

The wavelength of the carrier waves in a modern optical fiber communication network is close to ........ $nm$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module