A triangle and a parallelogram have the same | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Step $1$: Calculate the semi-perimeter $(s)$ of the triangle with sides $a = 10 \, cm$,$b = 17 \, cm$,and $c = 21 \, cm$.$s = (a + b + c) / 2 = (1

Vedclass · Accepted Answer

$7$

Vedclass · Answer

(B) Step $1$: Calculate the semi-perimeter $(s)$ of the triangle with sides $a = 10 \, cm$,$b = 17 \, cm$,and $c = 21 \, cm$.$s = (a + b + c) / 2 = (10 + 17 + 21) / 2 = 48 / 2 = 24 \, cm$.Step $2$: Calculate the area of the triangle using Heron's formula: $	ext{Area} = \sqrt{s(s-a)(s-b)(s-c)}$.$	ext{Area} = \sqrt{24(24-10)(24-17)(24-21)} = \sqrt{24 	imes 14 	imes 7 	imes 3} = \sqrt{7056} = 84 \, cm^2$.Step $3$: The area of the parallelogram is equal to the area of the triangle,so $	ext{Area} = 84 \, cm^2$.The formula for the area of a parallelogram is $	ext{base} 	imes 	ext{height}$.Given $	ext{base} = 12 \, cm$,we have $12 	imes 	ext{height} = 84$.$	ext{height} = 84 / 12 = 7 \, cm$.

$A$ triangle and a parallelogram have the same area. If the sides of the triangle are $10 \, cm$,$17 \, cm$,and $21 \, cm$,and the parallelogram stands on the base $12 \, cm$,find the height of the parallelogram. (in $, cm$)

Similar Questions

Find the area of a triangle whose sides are $13\, cm$,$14\, cm$,and $15\, cm$. (in $, cm^2$)

In quadrilateral $ABCD$,$AB = 40 \, cm$,$BC = 35 \, cm$,$CD = 48 \, cm$,$DA = 29 \, cm$ and $BD = 29 \, cm$. Find the area of quadrilateral $ABCD$. (in $, cm^2$)

An isosceles right triangle has an area of $8 \, cm^{2}$. The length of its hypotenuse is

In quadrilateral $ABCD$, one of its diagonals $AC$ measures $20 \, cm$. The altitudes on $AC$ from vertices $B$ and $D$ are $8 \, cm$ and $12 \, cm$ respectively. Find the area of quadrilateral $ABCD$ in $cm^2$.

In Heron's formula,$s$ represents ............

Vedclass Test Series

Exam Paper Generator

Online Exam Module