A transistor is connected in common emitter c | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given:Collector resistance $R_C = 1000 \, \Omega$Voltage drop across collector resistor $\Delta V_C = 0.6 \, V$Current gain $\beta = 24$The collec

Vedclass · Accepted Answer

$25$

Vedclass · Answer

(C) Given:Collector resistance $R_C = 1000 \, \Omega$Voltage drop across collector resistor $\Delta V_C = 0.6 \, V$Current gain $\beta = 24$The collector current $I_C$ is given by Ohm's law:$I_C = \frac{\Delta V_C}{R_C} = \frac{0.6 \, V}{1000 \, \Omega} = 0.6 	imes 10^{-3} \, A = 6 	imes 10^{-4} \, A$The relationship between collector current $I_C$ and base current $I_B$ is:$I_C = \beta 	imes I_B$Therefore,the base current $I_B$ is:$I_B = \frac{I_C}{\beta} = \frac{6 	imes 10^{-4} \, A}{24} = 0.25 	imes 10^{-4} \, A$Converting to microamperes $(\mu A)$:$I_B = 0.25 	imes 10^{-4} 	imes 10^6 \, \mu A = 25 \, \mu A$.

Similar Questions

The output characteristics of an $n-p-n$ transistor represent, ($I_C =$ collector current, $V_{CE} =$ potential difference between collector and emitter, $I_B =$ base current, $V_{BB} =$ voltage given to base, $V_{BE} =$ the potential difference between base and emitter)

In a transistor,the value of $\beta$ is $50$. The value of $\alpha$ is ........

In a junction transistor, the collector current changes by $6.8 \,mA$, if the emitter current is changed by $7 \,mA$. For such a transistor, the current amplification factor is

Vedclass Test Series

Exam Paper Generator

Online Exam Module