A truck is stationary and has a bob suspended | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) When the truck accelerates to the right with acceleration $a$,a pseudo force $F_{	ext{pseudo}} = ma$ acts on the bob in the opposite direction (i

Vedclass · Accepted Answer

to the left and the angle of inclination of the pendulum with the vertical is $	an^{-1}\left(\frac{a}{g}ight)$

Vedclass · Answer

(B) When the truck accelerates to the right with acceleration $a$,a pseudo force $F_{	ext{pseudo}} = ma$ acts on the bob in the opposite direction (i.e.,to the left) in the frame of the truck.Let $	heta$ be the angle the string makes with the vertical.In the equilibrium position of the bob in the truck's frame,the forces acting on the bob are the tension $T$,the gravitational force $mg$ acting downwards,and the pseudo force $ma$ acting to the left.Resolving the forces,we get:$T \sin 	heta = ma$$T \cos 	heta = mg$Dividing the two equations,we get:$	an 	heta = \frac{ma}{mg} = \frac{a}{g}$Therefore,$	heta = 	an^{-1}\left(\frac{a}{g}ight)$.Since the pseudo force acts to the left,the pendulum tilts to the left.

$A$ truck is stationary and has a bob suspended by a light string in a frame attached to the truck. The truck suddenly moves to the right with an acceleration of $a$. The pendulum will tilt:

Similar Questions

$A$ block is kept on a frictionless inclined surface with an angle of inclination '$\alpha$'. The incline is given a horizontal acceleration '$a$' to keep the block stationary relative to the incline. Then '$a$' is equal to:

$A$ body is thrown up in a lift with a velocity $u$ relative to the lift,and the time of flight is found to be $t$. The acceleration with which the lift is moving up is:

$A$ box of mass $m \, kg$ is placed on the rear side of an open truck accelerating at $4 \, m/s^2$. The coefficient of friction between the box and the surface below it is $0.4$. The net acceleration of the box with respect to the truck is zero. The value of $m$ is $[g = 10 \, m/s^2]$.

$A$ man weighing $60 \text{ kg}$ is in a lift moving down with an acceleration of $1.8 \text{ ms}^{-2}$. The force exerted by the floor on him is:

$A$ girl drops an apple from the window of a train which is moving on a straight track with speed increasing at a constant rate. The trajectory of the falling apple as seen by the girl is

Vedclass Test Series

Exam Paper Generator

Online Exam Module