(C) Let the total capacity of air in the tyre be $1$ unit.Rate of air leakage by the first puncture $= \frac{1}{9}$ unit/minute.Rate of air leakage by

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(C) Let the total capacity of air in the tyre be $1$ unit.Rate of air leakage by the first puncture $= \frac{1}{9}$ unit/minute.Rate of air leakage by the second puncture $= \frac{1}{6}$ unit/minute.Combined rate of air leakage $= \frac{1}{9} + \frac{1}{6} = \frac{2+3}{18} = \frac{5}{18}$ unit/minute.Time taken to make the tyre flat when both punctures are active $= \frac{1}{5/18} = \frac{18}{5} = 3.6$ minutes.Converting $0.6$ minutes to fractions: $0.6 = \frac{6}{10} = \frac{3}{5}$.Thus,the total time is $3 \frac{3}{5}$ minutes.

Competitive Quantitative Aptitude Time and Work and Wages Time and Work

Easy

$A$ tyre has two punctures. The first puncture alone would have made the tyre flat in $9 \,minutes$ and the second alone would have done it in $6 \,minutes.$ If air leaks out at a constant rate,how long does it take both the punctures together to make it flat? (in $minutes$)

A
$1 \frac{1}{2}$
B
$3 \frac{1}{2}$
C
$3 \frac{3}{5}$
D
$4 \frac{1}{4}$

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Time and Work and Wages

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Time and Work

$A, B$ and $C$ completed a work costing $Rs. 1800$. $A$ worked for $6$ days,$B$ for $4$ days and $C$ for $9$ days. If their daily wages are in the ratio of $5: 6: 4$,how much amount will be received by $A$ (in $Rs.$)?

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$A$ and $B$ working separately can do a piece of work in $9$ and $12$ days,respectively. If they work for a day alternately with $A$ beginning,the work would be completed in (in days):

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$4$ men and $6$ women earn $Rs. \, 1600$ by doing a piece of work in $5$ days. $3$ men and $7$ women earn $Rs. \, 1740$ by doing the same work in $6$ days. In how many days can $7$ men and $6$ women complete the same work while earning $Rs. \, 3760$?

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$A$ does $\frac{1}{5}$ of a work in a $week$. $B$ finishes the same in a fortnight. $B$ starts the work and works only for $3$ days. Thereafter,$A$ completes the job. In how many days will $A$ finish the remaining work?

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$A$ tyre has two punctures. The first puncture alone would have made the tyre flat in $9 \,minutes$ and the second alone would have done it in $6 \,minutes.$ If air leaks out at a constant rate,how long does it take both the punctures together to make it flat? (in $minutes$)

Similar Questions

$A, B$ and $C$ completed a work costing $Rs. 1800$. $A$ worked for $6$ days,$B$ for $4$ days and $C$ for $9$ days. If their daily wages are in the ratio of $5: 6: 4$,how much amount will be received by $A$ (in $Rs.$)?

$A$ and $B$ working separately can do a piece of work in $9$ and $12$ days,respectively. If they work for a day alternately with $A$ beginning,the work would be completed in (in days):

$A, B$ and $C$ can do a piece of work individually in $8, 10$ and $15$ days respectively. $A$ and $B$ start working,but $A$ quits after working for $2$ days. After this,$C$ joins $B$ until the completion of the work. In how many days will the work be completed?

$4$ men and $6$ women earn $Rs. \, 1600$ by doing a piece of work in $5$ days. $3$ men and $7$ women earn $Rs. \, 1740$ by doing the same work in $6$ days. In how many days can $7$ men and $6$ women complete the same work while earning $Rs. \, 3760$?

$A$ does $\frac{1}{5}$ of a work in a $week$. $B$ finishes the same in a fortnight. $B$ starts the work and works only for $3$ days. Thereafter,$A$ completes the job. In how many days will $A$ finish the remaining work?

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