A vertical pole of length 6, m casts a shadow | vedclass

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(C) Let $AB$ be the height of the tower and $CD$ be the height of the pole.Let $BE$ be the shadow of the tower and $DF$ be the shadow of the pole.Sinc

Vedclass · Accepted Answer

$42$

Vedclass · Answer

(C) Let $AB$ be the height of the tower and $CD$ be the height of the pole.Let $BE$ be the shadow of the tower and $DF$ be the shadow of the pole.Since the sun's rays fall at the same angle at the same time,the triangles formed by the objects and their shadows are similar.Therefore,$	riangle ABE \sim 	riangle CDF$ by $AA$ similarity criterion.This implies that the ratios of their corresponding sides are equal:$\frac{AB}{CD} = \frac{BE}{DF}$Given $CD = 6\, m$,$DF = 4\, m$,and $BE = 28\, m$.Substituting the values:$\frac{AB}{6} = \frac{28}{4}$$\frac{AB}{6} = 7$$AB = 7 	imes 6 = 42\, m$.Thus,the height of the tower is $42\, m$.

$A$ vertical pole of length $6\, m$ casts a shadow $4\, m$ long on the ground and at the same time a tower casts a shadow $28\, m$ long. Find the height of the tower. (in $m$)

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