A voltmeter having a resistance of 998 , Omeg | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The error in measurement is given by the difference between the actual $e.m.f.$ and the measured terminal voltage.Actual $e.m.f.$ $(E)$ = $2 \, V$

Vedclass · Accepted Answer

$4 	imes 10^{-3} \, V$

Vedclass · Answer

(C) The error in measurement is given by the difference between the actual $e.m.f.$ and the measured terminal voltage.Actual $e.m.f.$ $(E)$ = $2 \, V$.The circuit consists of the cell (with internal resistance $r = 2 \, \Omega$) and the voltmeter (with resistance $R = 998 \, \Omega$) in series.The current $(i)$ in the circuit is given by $i = \frac{E}{R + r} = \frac{2}{998 + 2} = \frac{2}{1000} = \frac{1}{500} \, A$.The measured voltage $(V)$ across the voltmeter is the terminal voltage of the cell, given by $V = E - ir$.Substituting the values: $V = 2 - (\frac{1}{500} 	imes 2) = 2 - \frac{2}{500} = 2 - 0.004 = 1.996 \, V$.The error in measurement = $E - V = 2 - 1.996 = 0.004 \, V = 4 	imes 10^{-3} \, V$.

$A$ voltmeter having a resistance of $998 \, \Omega$ is connected to a cell of $e.m.f.$ $2 \, V$ and internal resistance $2 \, \Omega$. The error in the measurement of $e.m.f.$ will be

Similar Questions

The sensitivity of a tangent galvanometer is increased if

We have a galvanometer of resistance $25\,\Omega$. It is shunted by a $2.5\,\Omega$ wire. The part of the total current that flows through the galvanometer is given as:

$A$ galvanometer coil has a resistance of $12\; \Omega$ and the meter shows full-scale deflection for a current of $3\; mA$. How will you convert the meter into a voltmeter of range $0$ to $18\; V$?

$A$ galvanometer has resistance $G$ and range $V_g$. How much resistance is required to read voltage up to $V$ volt?

Vedclass Test Series

Exam Paper Generator

Online Exam Module