A wave equation is y = 10^{-4} sin(60t + 2x), | vedclass

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(C) The standard wave equation is given by $y = A \sin(\omega t + kx)$.Comparing the given equation $y = 10^{-4} \sin(60t + 2x)$ with the standard equ

Vedclass · Accepted Answer

Wavelength of the wave is $\pi 	ext{ m}$.

Vedclass · Answer

(C) The standard wave equation is given by $y = A \sin(\omega t + kx)$.Comparing the given equation $y = 10^{-4} \sin(60t + 2x)$ with the standard equation,we get:Angular frequency $\omega = 60 	ext{ rad/s}$ and wave number $k = 2 	ext{ m}^{-1}$.Since the sign between $\omega t$ and $kx$ is positive,the wave travels in the negative $x$-direction.Frequency $f = \omega / (2\pi) = 60 / (2\pi) = 30/\pi 	ext{ Hz}$.Wave velocity $v = \omega / k = 60 / 2 = 30 	ext{ m/s}$.Wavelength $\lambda = 2\pi / k = 2\pi / 2 = \pi 	ext{ m}$.Comparing these results with the options,option $C$ is correct.

$A$ wave equation is $y = 10^{-4} \sin(60t + 2x)$,where $x$ and $y$ are in $m$ and $t$ is in $s$. Which of the following statements is correct?

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