A wave is given by y = 3 sin 2pi left( frac{t | vedclass

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(D) Comparing the given equation $y = 3 \sin 2\pi \left( \frac{t}{0.04} - \frac{x}{0.01} \right)$ with the standard wave equation $y = a \sin 2\pi \le

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$25 \, Hz, \; 7.4 	imes 10^4 \, cm/s^2$

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(D) Comparing the given equation $y = 3 \sin 2\pi \left( \frac{t}{0.04} - \frac{x}{0.01} ight)$ with the standard wave equation $y = a \sin 2\pi \left( \frac{t}{T} - \frac{x}{\lambda} ight)$:$1$. The time period $T = 0.04 \, s$.$2$. The frequency $f = \frac{1}{T} = \frac{1}{0.04} = 25 \, Hz$.$3$. The amplitude $a = 3 \, cm$.$4$. The angular frequency $\omega = \frac{2\pi}{T} = \frac{2\pi}{0.04} = 50\pi \, rad/s$.$5$. The maximum acceleration of a particle is given by $a_{max} = \omega^2 a$.$a_{max} = (50\pi)^2 	imes 3 = 2500 	imes \pi^2 	imes 3 = 7500 	imes 9.8696 \approx 7.4 	imes 10^4 \, cm/s^2$.

$A$ wave is given by $y = 3 \sin 2\pi \left( \frac{t}{0.04} - \frac{x}{0.01} \right)$,where $y$ is in $cm$. The frequency of the wave and the maximum acceleration of the particle are:

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