x- अक्ष के अनुदिश गतिमान एक तरंग का समीकरण y( | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) तरंग का सामान्य समीकरण $y(x, t) = A \cos(kx - \omega t)$ होता है।यहाँ,$k = \alpha$ और $\omega = \beta$ है।तरंग संख्या $k$ का सूत्र $k = \frac{2\pi

Vedclass · Accepted Answer

$\alpha = 25.00\pi, \beta = \pi$

Vedclass · Answer

(A) तरंग का सामान्य समीकरण $y(x, t) = A \cos(kx - \omega t)$ होता है।यहाँ,$k = \alpha$ और $\omega = \beta$ है।तरंग संख्या $k$ का सूत्र $k = \frac{2\pi}{\lambda}$ है।दिया गया है $\lambda = 0.08 \ m$,इसलिए $\alpha = \frac{2\pi}{0.08} = 25\pi \ rad/m$।कोणीय आवृत्ति $\omega$ का सूत्र $\omega = \frac{2\pi}{T}$ है।दिया गया है $T = 2.0 \ s$,इसलिए $\beta = \frac{2\pi}{2.0} = \pi \ rad/s$।अतः,सही विकल्प $A$ है।

Similar Questions

Assertion: The ferromagnetic substance does not obey Curie's law.
Reason: At Curie point, a ferromagnetic substance starts behaving as a paramagnetic substance.

One litre of oxygen at a pressure of $1\, atm$ and two litres of nitrogen at a pressure of $0.5\, atm$ are introduced into a vessel of volume $1\, L$. If there is no change in temperature,the final pressure of the mixture of gas (in $atm$) is

The covalent alkaline earth metal halide $(X = Cl, Br, I)$ is

Which of the following is $NOT$ a characteristic of Phylum $Annelida$?

If $\bar{M}_w$ is the weight average molecular weight and $\bar{M}_n$ is the number average molecular weight of a polymer,the poly dispersity index $(PDI)$ of the polymer is given by

Vedclass Test Series

Exam Paper Generator

Online Exam Module