A wave travelling in the positive x-direction | vedclass

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Question

(C) wave travelling in the positive $x-$direction is represented by the equation:$y = A \sin \left( \frac{2\pi}{\lambda} (vt - x) \right)$Given values

Vedclass · Accepted Answer

$y = 0.2\sin \left[ {2\pi \left( {6t - \frac{x}{{60}}} \right)} \right]$

Vedclass · Answer

(C) wave travelling in the positive $x-$direction is represented by the equation:$y = A \sin \left( \frac{2\pi}{\lambda} (vt - x) \right)$Given values are $A = 0.2\;m,$ $v = 360\;m/s,$ and $\lambda = 60\;m.$Substituting these values into the equation:$y = 0.2 \sin \left( \frac{2\pi}{60} (360t - x) \right)$$y = 0.2 \sin \left( 2\pi \left( \frac{360}{60}t - \frac{x}{60} \right) \right)$$y = 0.2 \sin \left[ 2\pi \left( 6t - \frac{x}{60} \right) \right]$Thus,the correct expression is $y = 0.2 \sin \left[ 2\pi \left( 6t - \frac{x}{60} \right) \right].$

$A$ wave travelling in the positive $x-$direction with amplitude $A = 0.2\;m$ has a velocity of $v = 360\;m/s.$ If the wavelength $\lambda = 60\;m,$ then the correct expression for the wave is:

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