A wave travelling in the -z direction having | vedclass

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Question

(A) The general equation for a wave travelling in the $-z$ direction is given by $x = A \sin(\omega t + kz)$.Given:Amplitude $A = 1 \ m$.Wavelength $\

Vedclass · Accepted Answer

$x = \sin(2t + 2z)$

Vedclass · Answer

(A) The general equation for a wave travelling in the $-z$ direction is given by $x = A \sin(\omega t + kz)$.Given:Amplitude $A = 1 \ m$.Wavelength $\lambda = \pi \ m$.Frequency $f = \frac{1}{\pi} \ Hz$.Angular frequency $\omega = 2\pi f = 2\pi 	imes \frac{1}{\pi} = 2 \ rad/s$.Wave number $k = \frac{2\pi}{\lambda} = \frac{2\pi}{\pi} = 2 \ m^{-1}$.Substituting these values into the general equation,we get:$x = 1 \sin(2t + 2z)$.Thus,the correct option is $A$.

$A$ wave travelling in the $-z$ direction having displacement along the $x$ direction as $1 \ m$,wavelength $\pi \ m$,and frequency $\frac{1}{\pi} \ Hz$ is represented by:

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